The graph of the linear equation x – ky – 10 =0 passes through the point (11,5).
Find the value of k
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Answer:
3x−ky=8
Put (1,−1) in it
3+k=8
k=5
Another point on this3x−5y=8
can be (6,2)
=3×6−5×2
=18−10=8
Graph of line is
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