The graph of the polynomial 4x²-8x+3 cuts the x-axis at ________ and ________ points.
(a) (3/4, 0), (1/2, 0)
(b) (3/2, 0), (1/2, 0)
(c) (3/2, 0), (1/6, 0)
(d) (7/2, 0), (3/2, 0)
Answers
Hi mate here your answer
Answer: b
Answer: bExplanation: The graph of the polynomial cuts the x-axis. Only the zeros of the polynomial cut the x-axis.
Answer: bExplanation: The graph of the polynomial cuts the x-axis. Only the zeros of the polynomial cut the x-axis.4x2-8x+3=0
Answer: bExplanation: The graph of the polynomial cuts the x-axis. Only the zeros of the polynomial cut the x-axis.4x2-8x+3=04x2-6x-2x+3=0
Answer: bExplanation: The graph of the polynomial cuts the x-axis. Only the zeros of the polynomial cut the x-axis.4x2-8x+3=04x2-6x-2x+3=02x(2x-3)-1(2x-3)=0
Answer: bExplanation: The graph of the polynomial cuts the x-axis. Only the zeros of the polynomial cut the x-axis.4x2-8x+3=04x2-6x-2x+3=02x(2x-3)-1(2x-3)=0(2x-3)(2x-1)=0
Answer: bExplanation: The graph of the polynomial cuts the x-axis. Only the zeros of the polynomial cut the x-axis.4x2-8x+3=04x2-6x-2x+3=02x(2x-3)-1(2x-3)=0(2x-3)(2x-1)=0x=3/2,1/2
2Hence, the graph of the polynomial cuts the x-axis at (3/2, 0) and (1/2, 0).