the graph of the quadratic relation y=x^{2}-3x-4
for what value or values of x is y=0?
a)x=-1 only
b)x=-4 only
c)x=-1 and x=-4
d)x=-1 and x=4
what is the answer
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Step-by-step explanation:
x²-3x-4=y
x²-3x-4=0
Therefore, by splitting the middle term
x²+x-4x-4=0
x(x+1)-4(x+1)=0
(x-4) (x+1)=0
Therefore,
x-4=0 or x+1=0
x=4 and x= -1
i.e. option d)
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