The graph of y = f(x), where f(x) is a quadratic polynomial meets the
x-axis at A(–2, 0) and B(–3,0), then the expression for f(x) is :
(a) x 2 +5x + 6 (b) x 2 - 5x + 6 (c)x 2 +5x- 6 (d) x 2 -5x– 6
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Answer:
given A(-2, 0) and B(-3, 0)
to find the polynomial f(x)
from the coordinates of A and B, it is evident that the curve intersects the x axis at -2 and -3
therefore - 2 and - 3 are the zeros of the polynomial f(x)
therefore f(x) is given by
x² - x(sum of zeros) + product of zeros
=> x² - x(-2 -3) + (-2)(-3)
=> x² + 5 x + 6
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