The graph of y=x^2+3x is shifted 3 units to the right. This graph is then vertically stretched by a factor of 6 and reflected across the x-axis. Finally, the graph is shifted 8 units upward
WRITE THE EQUATION
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y = x² + 3 x
New axes are X and Y.
Shift right, X = x + 3
Stretch vertically by a factor of 6 : Y = 6y
Reflected across x-axis : Y becomes -Y => Y = -6y
Graph shifted 8 units upwards : Y becomes Y+8 => Y = -6y+8
So, x = X-3 and y = (8-Y)/6
Substitute this in the original equation for the graph:
(8-Y)/6 = (X-3)² + 3 (X-3) = (X-3)(X-3+3) = X² - 3X
8 - Y = 6 X² - 18 X
Y = 8 - 6 X² + 18 X or Y = -6 (X - 3/2)² + 43/2
So equation of the graph: y = 8 - 6 x² + 18 x or -6 (x - 3/2)² + 43/2
New axes are X and Y.
Shift right, X = x + 3
Stretch vertically by a factor of 6 : Y = 6y
Reflected across x-axis : Y becomes -Y => Y = -6y
Graph shifted 8 units upwards : Y becomes Y+8 => Y = -6y+8
So, x = X-3 and y = (8-Y)/6
Substitute this in the original equation for the graph:
(8-Y)/6 = (X-3)² + 3 (X-3) = (X-3)(X-3+3) = X² - 3X
8 - Y = 6 X² - 18 X
Y = 8 - 6 X² + 18 X or Y = -6 (X - 3/2)² + 43/2
So equation of the graph: y = 8 - 6 x² + 18 x or -6 (x - 3/2)² + 43/2
kvnmurty:
i hope that is easy enough to understand
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