Question

The graph of y= x^3- 4x cuts x-axis at (-2,0), (0,0) and (2,0). The zeroes of x^3 - 4x are
(a) 0,0,0
(b) -2,2,2
(c) -2,0,2
(d) -2, -2, 2​

Answer 1

The zeroes of polynomial are -2,0 and 2

Option (c) is correct

Step-by-step explanation:

The graph of $y=x^3-4x$ cut x-axis at (-2,0), (0,0) and (2,0).

If graph cut x-axis this is zeros of the polynomial.

The x value of points would be zeroes.

So, zeroes are -2,0,2

$y=x^3-4x$

Factor it

$y=x(x^2-4)$

$y=x(x-2)(x+2)$

Set the value of y is 0

$x(x-2)(x+2)=0$

So, x=-2,0,2

Hence, the zeroes of polynomial are -2,0 and 2

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