The graph shows the motion of a car on its trip home,
(i) How far from home was the car initially ?
(ii) If the car started its homeward journey at 8.30 a.m., at what time
did it reach home ?
(iii) Find the speed of the car between :
(a) A and B (b) B and C
300-
Distance (km)
Answers
Answer:
see the graph and show distance between
Given:
Graph between distance and time is given,
Car started its journey at 8:30 am.
To Find:
1. Initial distance from home.
2. Time of reaching home.
3.Find the speed of the car between a) A and B
b) B and C
Solution:
As we can comprehend from the graph,
1. Initial distance = 300 kms, where the x coordinate is zero means the time is zero.
Initial Distance= 300 km
2. time of reaching home= 10 hrs, where the x coordinate is zero means the distance is covered.
Time of reaching home= 10 hrs.
He started at 8:30 am , so he will reach home at 8:30+10= 6:30 PM
Time of reaching home= 6:30PM
3. Speed = total distance / total time.
Time taken from A to B , T₁ = 4-0
=4 hrs.
distance from A to B , D₁= 300-100
=2000 km
time taken from B to C , T₂ = 10-4
=6 hrs.
Distance from B to C , D₂= 100-0
= 100km
a) Speed between A and B= Distance between A and B/ time between A and B.
S₁ = 200/4
S₁ =50km/hr
b) Speed between B and C= Distance between B and C/ time between B and C.
S₂=100/6
S₂ =16.66km/hr
