Question

The graph shows the variation of voltage V across the
plates of two capacitors A and B versus increase of
charge Q stored on then. Which of the two capacitors
have higher capacitance? Give reason for your answer
​

Answer 1

Answer:

Capacitor A has higher capacitance.

Explanation:

Capacitance C=Q/V

Therefore, C is directly proportional to charge Q and inversely proportional to Voltage V.

Out of the two capacitor A and B. A has more charge and less voltage when compared to capacitor B.

Hence, Capacitor A has higher capacitance.

Answer 2

Answer:

Capacitor A have higher capacitance.

Explanation:

Given Voltage Vs Charge stored graphs of two capacitors A and B.

Capacitance is the ratio of the change stored to the variation in its electric potential, and is given by

                                     $C=\frac{Q}{V}$

From the graph, Q is same for both the capacitors.

So, the charge stored in capacitor A is $Q=C_{A} \times V_{A}$

and the charge stored in capacitor B is $Q=C_{B} \times V_{B}$

        Ratio of capacitance, $\frac{C_{A}}{C_{B}} =\frac{V_{B}}{V_{A}}$  

As $V_{B} > V_{A} \implies C_{B} < C_{A}$

Hence, Capacitor A have higher capacitance.