Question

The graph shows variation of displacemen
of a particle performing
S.H.M. with
time to which of the following
statements is correct From the graph
A) acceleration is maximum at time T.
B)the force is maximum at 3T/4.
C) velocity is zero at T/2.
D) the kinetic energy is equal to total energy at time T/4.​

Answer 1

Answer:

options B and C are correct

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Explanation:

Maximum velocity occurs at mean position (x=0).

Thus velocity is maximum at T/4 and 3T/4, not T/2.

Acceleration is maximum at extreme positions, thus at 0, T/2, T. Thus B is correct.

Force or acceleration is zero at mean position, i.e at T/4, 3T/4. Thus C is correct.

KE=TE when PE=0 which occurs at mean position.T/2 is extreme not mean, thus D is incorrect.