The grass in a field increases at a constant rate. 17 cows can eat up all grass in 30 days whereas it takes 24 days for 19 cows. 4 cows were sold fromn a herd after the herd had eaten grass for 6 days. It took 2 more days for the herd to eat up the grass. How many cows were in that herd?
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Answer:
The grass in a field increases at a constant rate. 17 cows can eat up all grass in 30 days whereas it takes 24 days for 19 cows. 4 cows were sold fromn a herd after the herd had eaten grass for 6 days. It took 2 more days for the herd to eat up the grass. How many cows were in that herd?
Step-by-step explanation:
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Answer:
In a field, the grass increases in a constant rate. 1717 cows can eat all the grass in the field in 3030 days. 1919 cows can eat all the grass in 2424 days. Suppose, a group of cows started eating grass for 66 days. Then 44 cows are sold. The rest cows took 22 more days to eat the remaining grass. What is the number of cows in the group?
My trying:
A cow eats a certain amount of grass in one day, call it cc. The field grows by a certain amount each day, call it gg.
The field has some initial amount of grass: ii
i+30g−17⋅30ci+24g−19⋅24c=0=0
i+30g−17⋅30c=0i+24g−19⋅24c=0
Solving these two equations we get , g=9cg=9c . That means It takes 9 cows to eat one days in one day.