Question

the gravitational field due to a mass distribution is E=K /x² in the x direction .taking thegravitational potential to be zero at infinity, its value at a distance x is​

Answer 1

Explanation:

$\bf{\huge\mathcal{\boxed{\rm{\orange{Hey Mate:}}}}}$

E = - dV/dx

Integrating Edx from "x" to "∞" :

$\int \limits_x^{\infty} E dx</p><p>\qquad$

$\qquad=\int \large \frac{k}{x^2}$

$\qquad=-k \large\frac{x^{-1}}{1} \bigg|_x ^ {\infty}</p><p>$

So , V = k/x

Answer 2

Answer:

Answer in attachment

Hope it helps you ☺