Physics, asked by Shahnawaz5523, 11 months ago

The gravitational field in a region is given by e¯=(4i+j)n/kg. Workdone this field is zero when a particle is moved along the line

Answers

Answered by abhi178
1

a particle is moved along the line y + 4x = 6

The gravitational field in a region is given by e¯=(4i+j)n/kg. Workdone this field is zero when a particle is moved along the line

  • A. y + 4x = 6
  • B. 4y + x = 2
  • C. x + y = 5
  • D. none of these.

it is given that the gravitational field in a region is given by E = (4i + j) N/kg

let mass of a point particle is m.

so, force acting on particle in the region is F = mE = m(4i + j) N/kg.

taking y + 4x = 6,

when x = 0, y = 6

when y = 0, x = 3/2

so vector form of equation is S = (3/2 - 0)i + (0 - 6)j

= 3/2i - 6 j

as workdone is zero. means force and displacement are perpendicular to each other.

so, F.S = 0

LHS = (4i + j).(3/2 - 6j) = 6 - 6 = 0 = RHS

hence, a particle is moved along the line y + 4x = 6

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Answered by Anonymous
0

Answer:

The gravitational field in a region is given by e¯=(4i+j)n/kg. Workdone this field is zero when a particle is moved along the line

A. y + 4x = 6

B. 4y + x = 2

C. x + y = 5

D. none of these.

it is given that the gravitational field in a region is given by E = (4i + j) N/kg

let mass of a point particle is m.

so, force acting on particle in the region is F = mE = m(4i + j) N/kg.

taking y + 4x = 6,

when x = 0, y = 6

when y = 0, x = 3/2

so vector form of equation is S = (3/2 - 0)i + (0 - 6)j

= 3/2i - 6 j

as workdone is zero. means force and displacement are perpendicular to each other.

so, F.S = 0

LHS = (4i + j).(3/2 - 6j) = 6 - 6 = 0 = RHS

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