The gravitational field in a region is given by e¯=(4i+j)n/kg. Workdone this field is zero when a particle is moved along the line
Answers
a particle is moved along the line y + 4x = 6
The gravitational field in a region is given by e¯=(4i+j)n/kg. Workdone this field is zero when a particle is moved along the line
- A. y + 4x = 6
- B. 4y + x = 2
- C. x + y = 5
- D. none of these.
it is given that the gravitational field in a region is given by E = (4i + j) N/kg
let mass of a point particle is m.
so, force acting on particle in the region is F = mE = m(4i + j) N/kg.
taking y + 4x = 6,
when x = 0, y = 6
when y = 0, x = 3/2
so vector form of equation is S = (3/2 - 0)i + (0 - 6)j
= 3/2i - 6 j
as workdone is zero. means force and displacement are perpendicular to each other.
so, F.S = 0
LHS = (4i + j).(3/2 - 6j) = 6 - 6 = 0 = RHS
hence, a particle is moved along the line y + 4x = 6
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Answer:
The gravitational field in a region is given by e¯=(4i+j)n/kg. Workdone this field is zero when a particle is moved along the line
A. y + 4x = 6
B. 4y + x = 2
C. x + y = 5
D. none of these.
it is given that the gravitational field in a region is given by E = (4i + j) N/kg
let mass of a point particle is m.
so, force acting on particle in the region is F = mE = m(4i + j) N/kg.
taking y + 4x = 6,
when x = 0, y = 6
when y = 0, x = 3/2
so vector form of equation is S = (3/2 - 0)i + (0 - 6)j
= 3/2i - 6 j
as workdone is zero. means force and displacement are perpendicular to each other.
so, F.S = 0
LHS = (4i + j).(3/2 - 6j) = 6 - 6 = 0 = RHS