Question

The gravitational force between a body of 1kg and the earth.

Answer 1

Therefore heavy objects do not fall faster than light objects provided there is no air resistance. What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 1024 kg and radius of the earth is 6.4 × 106 m.)

hope it's help u ✌️✌️

Answer 2

To find:-

•Gravitational force between earth and a body of mass 1kg on it's surface

Solution:-

•Mass of earth(m1)=6×10²⁴kg

•Radius of earth(R)=6.4×10⁶m

•Value of G=6.67×10^-11

We know that-----

=>F=Gm1m2/R²

$= > \frac{6.67 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 1}{( {6.4 \times {10}^{6}) }^{2} }$

$= > \frac{6.67 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 1 }{6.4 \times {10}^{6} \times 6.4 \times {10}^{6} }$

$= > \frac{6.67 \times 6}{6 .4\times 6.4} \times 10 ^{ - 11 + 24 - 6 - 6}$

$= > 0.97 \times 10$

=>9.8N

Thus,the gravitational force is 9.8N