Question

The gravitational force between two bodies is1 N if the distance between them is doubled what will be the force between them

Answer 1

Answer:

If the distance between them is doubled.

Then,

Force between them is 0.25 N.

Explanation:

Given,

f1 = 1 N

Let r1 be r.

r2 is the double of r1.

Then,

r2 = 2r.

Gravitational force (f) is inversely proportional to the (r)^2.

$f \: \alpha \: \frac{1}{ {r}^{2} } \\ \frac{f1}{f2} \: = \: \: ( \frac{r2}{r1}) ^{2} \\ \frac{f1}{f2} \: = \: ( \frac{2r}{r} ) ^{2} \\ \frac{f1}{f2} \: = \:(2) ^{2} \\ \frac{1}{f2} \: = \: 4 \\ f2 \: = \: \frac{1}{4} \: newton \\ f2 \: = \: 0.25 \: newton$

Here,

f is the gravitational firce.

G is the gravitational constant.

m1 and m2 are the masses of the bodies.

r is the distance between two bodies.

r1 is the distance between two bodies in first case.

r2 is the distance between two bodies in second case.

If the distance between them is doubled.

Then,

Force between them is 0.25 N.