The gravitational force between two objects is 49 N. How much distance between these objects be decreased so that the force between them becomes double?
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The gravitational force of attraction between the bodies is inversely proportional to the square of the distance of seperation between them .
F proportional to 1/r^2
if the mass of the two bodies are same.
We can write
F1 proportional to 1/r1^2
F2 proportional to 1/r2^2
In the form of proportion
F1/F2 = r2^2/r1^2
F1 = 49N × 2 = 98N
F2= 49N
98/49 = r2^2/r1^2
2/1 = (R2/R1)^2
R2/R1 = √2
R1/R2 = 1/√2
The distance of seperation should be decreased by 1/√2 of the previous one so the force between the two bodies becomes doubled.
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