English, asked by divyashree34, 5 months ago

The gravitational force between two small objects decreases by 36% when the distance between them is increased by 4m. The original distance
between them in meter) is
08
O 10
O 12
0 16​

Answers

Answered by Anonymous
9

Answer:

Let initial force of attraction between two objects is F when distance between objects is r. But force of attraction decreased by 36% when the distance between them is increased by 4. We know, gravitational force is inversely proportional to square of distance between objects

Explanation:

\huge\text{ғᴏʟʟᴏᴡ ᴍᴇ}

\Large\text{❥PaLaK}

Answered by sameerronaldo12763
2

Let initial force of attraction between two objects is F when distance between objects is r.

But force of attraction decreased by 36% when the distance between them is increased by 4.

e.g., final force = F - 36% F = 0.64F

We know, gravitational force is inversely proportional to square of distance between objects.

so, = F1 = d²2

F2 d²1

or, odr = (r4)

or, 1/(0.8)? = (r + 4)/r =

or, 1/ 0.8 = (r + 4)/r =

or, r = 0.8r + 3.2

or, r = 16 m

hence, original distance between them is 16m

Similar questions