Question

The gravitational force of 733 Newton acts on Mahendra who has mass of 75 kg starting from rest what will be Mahendra’s Velocity after 1 second if he is falling down due to gravitational force of the earth.​

Answer 1

Given : The gravitational force of 733 Newton acts on Mahendra who has mass of 75 kg starting from rest

To Find : Velocity after 1 second if he is falling down due to gravitational force of the earth.​

Explanation:

gravitational force of 733 Newton

mass = 75 kg

F = mg

733 = 75g

g = 733/75 m/s^2

v = u + at

u =0 as start from rest

t = 1 sec

a = g = 733/75

v = 0 + (733/75)×1

v = 9.77 m/s

Velocity after 1 second = 9.77 m/s

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Answer 2

Given:

The gravitational force of 733 Newton acts on Mahendra who has mass of 75 kg starting from rest.

To find:

Mahendra’s velocity after 1 second?

Calculation:

Acceleration of Mahendra:

$\rm \:a = \dfrac{force}{mass}$

$\rm \implies \:a = \dfrac{733}{75}$

$\rm \implies \:a = 9.77 \: m {s}^{ - 2}$

Now, velocity after 1 second will be :

$\rm \: v = u + at$

$\rm \implies\: v = 0+ (9.77 \times 1)$

$\rm \implies\: v = 9.77 \: m {s}^{ - 1}$

So, velocity after 1 second is 9.77 m/s.