Question

The gravitational force of attraction between a stone weighing 2 kg and the earth moving 6 into 10 to the power 24 kg is 19.6 newtons what will be the acceleration produced in the earth

Answer 1

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Answer :- Given that-

Given that-Force = 19.6 N

Given that-Force = 19.6 NWeight of the Earth = 6× 10^24 kg

Given that-Force = 19.6 NWeight of the Earth = 6× 10^24 kgSince

Given that-Force = 19.6 NWeight of the Earth = 6× 10^24 kgSinceF = ma

Given that-Force = 19.6 NWeight of the Earth = 6× 10^24 kgSinceF = maSo,

Given that-Force = 19.6 NWeight of the Earth = 6× 10^24 kgSinceF = maSo,19.6 = 6×10^24 × a

Given that-Force = 19.6 NWeight of the Earth = 6× 10^24 kgSinceF = maSo,19.6 = 6×10^24 × a19.6 ÷ 6×10^24 = a

Given that-Force = 19.6 NWeight of the Earth = 6× 10^24 kgSinceF = maSo,19.6 = 6×10^24 × a19.6 ÷ 6×10^24 = aOr,

Given that-Force = 19.6 NWeight of the Earth = 6× 10^24 kgSinceF = maSo,19.6 = 6×10^24 × a19.6 ÷ 6×10^24 = aOr,a = 19.6÷ 6 × 10^24

Given that-Force = 19.6 NWeight of the Earth = 6× 10^24 kgSinceF = maSo,19.6 = 6×10^24 × a19.6 ÷ 6×10^24 = aOr,a = 19.6÷ 6 × 10^24a = 3.2666 × 10^-24 m/s^2

Given that-Force = 19.6 NWeight of the Earth = 6× 10^24 kgSinceF = maSo,19.6 = 6×10^24 × a19.6 ÷ 6×10^24 = aOr,a = 19.6÷ 6 × 10^24a = 3.2666 × 10^-24 m/s^2i.e, a = 3.3 × 10^-24 m/s^2 (approx)

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