the gravitational force of attraction between two bodies at a certain distance is 70 N.if the distance of separation between them is doubled, then find the percentage change in force of attraction?
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we know that,
if distance is doubled F2 becomes 1/4 F1
so F1 is 70,
distance is doubled.
so F2 =1/4 ×F1
therefore F2= 17.5N
plz mark as brainiest if it helps
if distance is doubled F2 becomes 1/4 F1
so F1 is 70,
distance is doubled.
so F2 =1/4 ×F1
therefore F2= 17.5N
plz mark as brainiest if it helps
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