Question

the gravitational force of attraction between two bodies is F1 if the mass of each body is doubled and the distance between them is halved then the gravitational force between them is F2 then
a) F1=F2. b) F2 = 4F1
c) F2 = 8F1. d) F2 = 16F1

Answer 1

Answer:

Explanation:

Gravitational Force:

An attraction between all mass-bearing objects; one mass-bearing object will draw another mass-bearing object; the strength of the attraction is directly proportional to the masses of the two objects and inversely proportional to the square of their distances.

Mathematically

F = $G m1 m2 / d{2}$

Universal law of gravitation

Where m1 and m2 are the masses of the objects in kilograms, d is the separation between them in metres, and G is the global gravitational constant (i.e., it has the same value across the universe).

$6.67 * 10^{-11} N m2/kg2 = G$

Given : The gravitational force of attraction between two bodies is $F1$

             The mass of each body is doubled and the distance between

              them is halved

Find:  To find the value of $F2$

Solution: $Fg$ $= G* m1*m2/d2$

               doubling both masses and cutting the distance in half

               $Fg = G * 2m1*2m2/( d/2)^{2}$

               $Fg = G*4*m1*m2/1/4*d^{2}$

               $Fg = G*m1*m2/d^{2} *16$

                $Fg = 16$

                $F2 = 16F1$

Hence option d is the correct

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