Question

The gravitational potential energy of a body of mass 0.5 kg increases by 100 J when it is taken to the top of a tower from the ground. If force of gravity on 1 kg is 10 N, what is the height of the tower ?
Please give me right answer ...​

Answer 1

Given :-

• Mass of body M=0.5kg
• Potential energy P.E=100J
• Force of gravity on 1 kg is 10 N

To find :-

the height of the tower.

Solution :-

we know,

➠ F = mg

➠ 10 = 1 × g

➠ g = 10 m/s²

so,

change in Potential energy = mg(h2 −h1)

= mg(h−0)

= mgh

Now, the height of the tower

$\sf 100 = mgh$

$\sf h = \dfrac{100}{0.5 \times 10}$

$\sf h = 20m$

Hence, the height of the tower is 20 m.