Question

The gravitational potential energy of a system of two particles such that one body is taken is t infinity is a) -(Gm_(1)m_(2))/(m) b) (GM_(1)m_(2))/(r) c) 0 d)-3Gm_1m_2/2r​

Answer 1

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Actually Welcome to the Concept of the Gravitation

Now basically here, we are going to apply the Gravitational Force law

The law states that, The Gravitational force between the two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

So applying this we get as,

F = GMm/r^2 and Potential Energy "U" is given as

U = -GMm/r

here, "G" is the gravitational constant

since here the one of the body is at a infinity distance,

so r tends to Infinity

U = -GMm/infinity

U is simultaneously zero

⭐so U = 0