The gravitational potential energy stored in a box of weight 200 kgf is 20000 J. Find the height at which the box is placed. ( Take 1 Kgf = 10N)
Answers
Answered by
55
Hello Mate!
Since we know that potential energy = mgh
And Force = mg
Since 1 kgf = 10 N
200 kgf = 200 × 10 N
= 2000 N
Now, substituting values we get
20000 J = 2000 N × s
10 m = s
Hence box is placed 10 m above.
Have great future ahead!
Since we know that potential energy = mgh
And Force = mg
Since 1 kgf = 10 N
200 kgf = 200 × 10 N
= 2000 N
Now, substituting values we get
20000 J = 2000 N × s
10 m = s
Hence box is placed 10 m above.
Have great future ahead!
Sanskriti141:
nice dear
Answered by
27
here, w= 20000 j.
now, s=?
potential energy = mgh
therefore 20000= mgh
where f= ma
m=f÷a
m= 2000÷9.8
=204 kg.
therefore 20000= 204x 9.8xh
1999.2h= 20000
h= 20000÷1999.2
10m is the height.
now, s=?
potential energy = mgh
therefore 20000= mgh
where f= ma
m=f÷a
m= 2000÷9.8
=204 kg.
therefore 20000= 204x 9.8xh
1999.2h= 20000
h= 20000÷1999.2
10m is the height.
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