the greater and least resultant of two forces are 7 M and 3 M respectively if each of the force is increased by 3 and X applied at 60° the magnitude of the resultant is
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Hii friend,
By using parallelogram law of vectors, The formula is
F= √P²+q²+2pq cos theta
:-√(10)²+(6)²+2(10)(6)cos60°
F=√196
F= 14N
Though it is an average between greater and lesser magnitude,
F=14/2
F= 7N
Option (A) is correct.
Hope this helps you a little!!!
By using parallelogram law of vectors, The formula is
F= √P²+q²+2pq cos theta
:-√(10)²+(6)²+2(10)(6)cos60°
F=√196
F= 14N
Though it is an average between greater and lesser magnitude,
F=14/2
F= 7N
Option (A) is correct.
Hope this helps you a little!!!
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