Question

the greater by 1,
4. A man distributed his property amongst his son, daughter and wife. He gave one-third to
his son, two-fifths to his daughter and the remaining to his wife. If the wife's share was
*32,000, how much money did the man have?​

Answer 1

Answer:

Step-by-step explanationLet his total money be x

son's share →

3

x

​

daughter's →

4

x

​

remaining → wife =x−(

3

x

​

+

4

x

​

)

=x−

12

7x

​

=

12

5x

​

12

5x

​

=45000

x=

5

45000×12

​

=108000:

Answer 2

Answer:

The man had the money Rs. 120000.

Step-by-step-explanation:

Let the man had money Rs x.

Money given to his son = $\displaystyle{\sf\:\dfrac{1}{3}\:\times\:x}$

Money given to his son = $\displaystyle{\sf\:\dfrac{x}{3}}$

Money given to his daughter = $\displaystyle{\sf\:\dfrac{2}{5}\:\times\:x}$

Money given to his daughter = $\displaystyle{\sf\:\dfrac{2x}{5}}$

Money given to his wife = Remaining money by distributing amongst son and daughter

⇒ Money given to his wife = Total money - ( Sum of money given to son and daughter )

⇒ Money given to his wife = $\displaystyle{\sf\:x\:-\:\left(\:\dfrac{x}{3}\:+\:\dfrac{2x}{5}\:\right)}$

$\displaystyle{\implies\sf\:x\:-\:\left(\:\dfrac{5\:\times\:x\:+\:2x\:\times\:3}{3\:\times\:5}\:\right)\:=\:32000\:\:\:-\:-\:[\:Given\:]}$

$\displaystyle{\implies\sf\:x\:-\:\left(\:\dfrac{5x\:+\:6x}{15}\:\right)\:=\:32000}$

$\displaystyle{\implies\sf\:x\:-\:\dfrac{11x}{15}\:=\:32000}$

$\displaystyle{\implies\sf\:\dfrac{15\:\times\:x\:-\:11x}{15}\:=\:32000}$

$\displaystyle{\implies\sf\:\dfrac{15x\:-\:11x}{15}\:=\:32000}$

$\displaystyle{\implies\sf\:\dfrac{4x}{15}\:=\:32000}$

$\displaystyle{\implies\sf\:4x\:=\:32000\:\times\:15}$

$\displaystyle{\implies\sf\:x\:=\:\dfrac{\cancel{32000}\:\times\:15}{\cancel{4}}}$

$\displaystyle{\implies\sf\:x\:=\:8000\:\times\:15}$

$\displaystyle{\implies\underline{\boxed{\red{\sf\:x\:=\:120000}}}}$

∴ The man had the money Rs. 120000.