The greater of two consecutive even integers is 6 less than 3 times the lesser. Find the integers.
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The greater of two consecutive even integers is 6 less than three times the lesser. Find the integers.
Consecutive even integers differ by 2
Let the required two consequtive even integers be a and a+2
The greater of a and (a+2) ia 6 less than 3 times the lesser.
That is (a+2)is 6 less than 3a
That is 3a - (a+2) = 6
3a - a -2 = 6
(3a-a) = 6 +2
2a = 8
a = 4
The required consecutive even numbers are 4 and 6
Verification:
The greater should be 6 less than 3times the smaller.
3 times the smaller is 3a = 12
And 6 is of course 6 less than 12
Hence our answer is right
Answered by
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Answer:
Let the first no. = ✖️
Second no. = x+2
A.T. Q.
✖️ +✖️ +2+6 = 3✖️
2✖️ +8 = 3✖️
3✖️ -2✖️ = 8
✖️ = 8
therefore, first no. = ✖️ = 8
Second no. = ✖️ +2 = 8+2=10
=
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