Math, asked by mvramana4776, 11 months ago

The greater of two consecutive even integers is 6 less than 3 times the lesser. Find the integers.

Answers

Answered by shaurya2424
1

The greater of two consecutive even integers is 6 less than three times the lesser. Find the integers.

Consecutive even integers differ by 2

Let the required two consequtive even integers be a and a+2

The greater of a and (a+2) ia 6 less than 3 times the lesser.

That is (a+2)is 6 less than 3a

That is 3a - (a+2) = 6

3a - a -2 = 6

(3a-a) = 6 +2

2a = 8

a = 4

The required consecutive even numbers are 4 and 6

Verification:

The greater should be 6 less than 3times the smaller.

3 times the smaller is 3a = 12

And 6 is of course 6 less than 12

Hence our answer is right

Answered by ahanmishra17
1

Answer:

Let the first no. = ✖️

Second no. = x+2

A.T. Q.

✖️ +✖️ +2+6 = 3✖️

2✖️ +8 = 3✖️

3✖️ -2✖️ = 8

✖️ = 8

therefore, first no. = ✖️ = 8

Second no. = ✖️ +2 = 8+2=10

=

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