The greatest 4-digit number exactly divisible
by 8, 10 and 12 is
Answers
Answer:
2 is the answer
Step-by-step explanation:
pls follow me and mark my answer as brainliest
Answer:
9960 is the greatest 4 digit number divisible by 8, 10, and 12.
Step-by-step explanation:
Let the number be x
So, firstly we can say that,
1000 < x < 9999
Now, we know that,
x must be divisible by 8, 10 and 12, then that number must be a common multiple of 8, 10, and 12.
Hence, we take their LCM,
LCM (8, 10, 12) = 120
Now, remember I said 1000 < x < 9999, this is because neither 1000 nor 9999 is a multiple of 120, that is why I said that.
So, the 1st common multiple is 120.
2nd common multiple will be 120 × 2 = 240
3rd common multiple will be 120 × 3 = 360
.
.
.
and so on.
Now, this number is between 1000 and 9999
To find that number, we can either do it by trial and error, or divide 9999 by 120 and find the Quotient, this is because 9999 is the greatest 4 digit number.
9999 ÷ 120 = (Q = 83) and (R = 39)
Thus,
83rd common multiple is the largest 4 digit number divisible by 8, 10, and 12, as the Quotient is 83, with a remainder.
Thus,
x = 120 × 83
x = 9960
Hence,
9960 is the greatest 4 digit number divisible by 8, 10, and 12.
we can check this,
1000 < 9960 < 9999
also,
9960 ÷ 8 = 1245
9960 ÷ 10 = 996
9960 ÷ 12 = 830
So, it is true
Hope it helped and believing you understood it........All the best