Question

The greatest 5 digit no. When divided by 4 5 6 7 8 9 leave remaider 3 4 5 6 7 8 respectively

Answer 1

Answer:

The greatest number of 5 digits,that give remainder of 5 when divided by 8 and 9 respectively is  99941.

Step-by-step explanation:Greatest 5-Digit number = 99999

LCM of 8 and 9,

8 = 2 × 2 × 2

9 = 3 × 3

LCM = 2 × 2 × 2 × 3 × 3 = 72

Find Greatest 5-digit number divisible by 8 and 9 by dividing 99999 by 72.

In division we get,

Quotient = 1388

Remainder = 63

So, the greatest 5-digit number divisible by 8 and 9 = 99999 - 63 = 99936

Required number = 99936 + 5 = 99941

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