The greatest and least resultant of two forces acting at a point is 10N and 6N respectively . If each of force is increased by 3N , find the resultant of new forces when acting at a point at angle of 90' with each other
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Answered by
266
If two forces are F1 and F2 then,
F1 + F2 = 10N
F1 - F2 = 6N
Add above two equations
2F1 = 16
F1 = 8N
From first equation
F2 = 10 - 8 = 2N
When increased by 3N
F1 = 8N + 3N = 11N
F2 = 2N + 3N = 5N
Resultant = sqrt(11^2 + 5^2) = sqrt(121 + 25) = sqrt(146) = 12.083N
F1 + F2 = 10N
F1 - F2 = 6N
Add above two equations
2F1 = 16
F1 = 8N
From first equation
F2 = 10 - 8 = 2N
When increased by 3N
F1 = 8N + 3N = 11N
F2 = 2N + 3N = 5N
Resultant = sqrt(11^2 + 5^2) = sqrt(121 + 25) = sqrt(146) = 12.083N
aayushsh:
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Answered by
35
Answer:
Explanation:
Solution,
Let P and Q be the two forces.
Then,
Greatest resultant = P + Q = 29 N ..... (i)
Least resultant = P - Q = 5 N ..... (ii)
On Solving eq (i) and (ii), we get
P = 17 N and,
Q = 12 N
When each force is increased by 3 N,
Then,
New forces are
p = P + 3 = 17 + 3 = 20 N
q = Q + 3 = 12 + 3 = 15 N
As the new forces actat right angle to each other,
Then their resultant are,
R = √p² + q²
R = √20² + 15²
R = √625
R = 25 N
If resultant R makes angle β with the force p, then
tan β = p/q
tan β = 15/20
tan β = 0.75
or β = tan (0.75)
β = 36°52'.
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