Math, asked by mannavapavani1846, 11 months ago

The greatest common divisor of two numbers a and b is 22. The least common multiple of a and b is 2002, if a has fewer divisors than b, what is a b

Answers

Answered by aseemkumar
0

Answer:

22 and 2002 is the best answer of your question

Answered by chpriyanka61
1

Answer:

Step-by-step explanation:In this greatest common divisor means  HCF is given as h=22

and the other one is least common multiple i.e,LCM= 2002

HCF is taken as " h "and it has two numbers of a and b i.e,ha and hb

now LCM=h*a*b=hab

we know that    hab=2002

                   =>   22*a*b=2002

                          22ab=2002

                           ab=2002/22

                            ab=91

now we got ab=91 but we want the values of ' a ' and 'b'.

so if we multiply any two numbers we should get the answer 91.

=>  91*1=91  (i.e, a=91, b=1)                        

then ha=22*91=2002  

        hb=22*1=22

adding of ha+hb gives the answer=2024

if the answer in ur options is 2024 then go for another multiple of 91 number.

13*7=91

ha=22*13=286

hb=22*7=154

then ha+hb=286+154=440

this would be ur answer if this number is  in ur options. or else 2024

         

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