Math, asked by yashkothari42034, 4 months ago

The greatest common factor of 28a²b2c and 35 abc² is

Answers

Answered by TJain9

1

Answer:

7abc

Step-by-step explanation:

Factorize

$28a^{2}b^{2}c * 35abc^{2}\\7(4a^{2}b^{2}c * 5abc^{2})\\7abc(4ab * 5c)$

Therefore

7abc is the highest common factor

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