Math, asked by saranshrock769, 9 months ago

The greatest five digit number, when divided by 5, 6 and 7 leaves the remainder 2, is

Answers

Answered by neev3
0

Answer:

the number is 99962

Step-by-step explanation:

hope it helpful to you

Answered by shivakumar0820
3

Answer:

The greatest five digit number when divided by 5, 6 and 7 leaves the remainder 2 is 99962

MARK ME BRAINLINEST

Step-by-step explanation:

First we need to see how to find a number that gives remainder two when divided 5, 6, and 7 individually.

This can be found by considering the LCM of 5, 6, and 7. As these are relative prime, the LCM of them is simply 5 \times 6 \times 7 = 210.

So now any multiple of 210 added to 2 would give remainder 2 when divided by any of these three numbers 5, 6, and 7.

We need to find a multiple that gives greatest five-digit number when added to 2.

Try the division 105/210 and find the floor of it:

Integer part of 105210    is 476

Now consider 476×210+2=99962- the required five-digit number

Similar questions