the greatest four digits which when divided by 8,12 and 16 gives remainder 2 is
a)9984 b) 9985 c) 9986 d) 9987
My answer is c. 9986
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Step-by-step explanation:
we divided 9999 by the LCM 48. And we have remained 15. So we subtracted this remainder from the greatest four digits number and add with qns's remainder 2 that leaves in every case. (9999-15)+2=9986 .
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