Question

the greatest integer that divides 70 an 125 leaving remainder 5 an 8 respectively is​

Answer 1

Answer:

Subtracting remainders from the numbers,

65 = (70 - 5), 117 = (125 - 8), which is divisible by the required number.

Required number = HCF of 65, 117          

117 = 65 × 1 + 52        

65 = 52 × 1 + 13

52 = 13 × 4 + 0

HCF = 13

13 is the largest number required to divide 70 and 125, leaving remainder 5 an 8 respectively.

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Answer 2

Answer:

Number when divides 70 and 125 leaves remainders 5 and

8, then

70−5=65

125−8=117

then HCF of 65 and 117 is

65=5×13

117=3×3×13

Hence, HCF of 65 and 117 is 13.

13 is the largest number which divides 70 and 125 and leaves remainders 5 and 8.

Hope it helps you.