Question

The greatest length of steel wire that can hang vertically without breaking is 8×10^8N/m^2 density 8×10^3kg/m^3 g=10m/s^2

Answer 1

$\hugel\underline{\overline{\mid{\bold{\orange{Given-}}\mid}}}$

• The breaking stress of the steel wire is$\sigma =$ $8\times 10^8 N/m^2$

• The density of the steel wire is $p$=$8\times 10^3 N/m^3$

Formula used-

$\hugel\underline{\overline{\mid{\bold{\red{F= Alpg}}\mid}}}$

Here,

• The cross section area of the steel wire is A

• The length of the steel wire is l
• F is the force

$\hugel\underline{\overline{\mid{\bold{\green{SoLution-}}\mid}}}$

we know that,

$\boxed{\sigma = \dfrac{F}{A}}$

put value of F in this formula we get,

$\sigma = \dfrac{Alpg}{A}$

$\sigma = lpg$

$l= \dfrac{8\times 10^8}{10\times 8 \times 10^3}$

$\boxed {l= 10^4m}$