Question

the greatest no which divides 134 and 167 leaving 2 as remainder with process​

Answer 1

Answer:

Step-by-step explanation:

The largest number which divides 615 and 963 leaving remainder 2 in each case => HCF.

And let the HCF be x.

To make 134 and 167 completely divisible by x we have to sub. 2 from 134 and 167.

134-2=132,167-2=165

165 = 3*5*11

132= 2*2*3*11

⇒ x =3*11⇒x=33

Therefore the greatest number which divides 134 and 167 leaving 2 as remainder in each case as 33.

Answer 2

Answer:

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Step-by-step explanation:

the largest no. which divides 167 and 134 is 33

134-2=132            167-2=165

165=3*5*11

132=2*2*3*11

x=3*11=33

therefore the greatest no. which divides 134 and 167 leaving 2 as a remainder is 33