the greatest no. which divides 270 & 84 leaving a remainder 2 in each case
Answers
Given:
The greatest no. which divides 270 & 84 leaves a remainder 2 in each case
To find:
The greatest number
Solution:
(1). Since both the numbers when divided leaves 2 as their remainders in each case, so we will subtract 2 from both the numbers,
270 - 2 = 268
84 - 2 = 82
(2). We will find the H.C.F. of 268 and 82 by using the prime factorisation method
Factors of 268 & 82:
268 = 2 × 2 × 67
82 = 2 × 41
H.C.F:
H.C.F. of 268 & 82 = 2
Thus, the greatest no. which divides 270 & 84 leaves a remainder 2 in each case is 2.
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