Question

The greatest number of 4 digit which is divisible by 20, 25, 60 and 100 is

Answer 1

Answer:

1800

Step-by-step explanation:

1800 ÷ 20 = 90

1800 ÷ 25 = 72

1800 ÷ 60 = 30

1800 ÷ 100 = 18

Answer 2

The required number is 9900 which is divisible by 20, 25, 60 and 100.

Step-by-step explanation:

To find : The Greatest 4 digit which is divisible by 20, 25, 60 and 100 ?

Solution :  

The greatest 4-digit number is 9999.

Now, Find the LCM of 20, 25, 60 and 100

2 | 20  25  60  100

2 | 10   25   30   50

5 |  5   25   15    25

5 |  1     5     3    5

3 |  1     1      3     1

  |  1     1      1    1

$LCM( 20, 25, 60,100)=2\times 2\times 3\times 5\times 5$

$LCM( 20, 25, 60,100)=300$

Divide 9999 by 300 so that we get the remainder,

$9999 =300 \times 33+ 99$

Remainder is 99.

Now, Subtract the remainder from 9999.

$9999-99=9900$

Therefore, The required number is 9900 which is divisible by 20, 25, 60 and 100.

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