The greatest number of four digits which is divisible by 15, 25, 40, and 75 is
1) 9000.
2) 9400.
3) 9600.
4) 9800.
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Answered by
6
Answer:
Greatest number of 4-digits is 9999. L.C.M. of 15, 25, 40 and 75 is 600. On dividing 9999 by 600, the remainder is 399. ∴ Required number (9999 - 399) = 9600.
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Answered by
0
Answer:
The greatest number divisible by 15, 25, 40 and 75 will be 600*8*k=4800*k<=9999. So with k=2 we get 4800*2=9600 as the greatest number of four digits which is divisible by 15, 25, 40 and 75. 9600/75=128, 9600/40=240, 9600/25=384 and 9600/15=640.
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