The greatest number that divides 3960,4455,2970, without leaving Any remainder
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Answered by
0
Answer:
Answer is 495 hope it helps
Step-by-step explanation:
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Answered by
1
Answer:
495
Step-by-step explanation:
We need to find highest common factor (HCF)of 3960,4455 and 2970
Let's get prime factors of each:
3960= 2^3 x 3^2 x 5 x 11
4455= 3^4 x 5 x 11
2970= 2 x 3^3 x 5 x 11
HCF(3960,4455,2970)= 3^2*5*11=495
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