Question

the greatest number that divides 4410,5040 and 4725 exactly without leaving any remainder

Answer 1

Answer:

HCF(4410, 5040 ,4725) = 3 × 3 × 5 × 7 = 315

Step-by-step explanation:

4410 = 2 × 3 × 3 × 5 × 7 × 7

5040 = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 7

4725 = 3 × 3 × 3 × 5 × 5 × 7

HCF(4410, 5040 ,4725) = 3 × 3 × 5 × 7 = 315

Answer 2

Step-by-step explanation:

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