the greatest number that will decide 243 and 314 leaving remainders 5 and 6 respectively is.
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firstly we will subtract 5 and 6 from 243 and 314
so, 243-5=238 and 314-6=308
so the required greatest number will be HCF of 238 and 308.
HCF of 238 and 308 will be:-14
so, the greatest number that will divide 243 and 314 leaving remainder 5 and 6 respectively will be:-14.
HOPE THIS WILL HELP YOU.
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