Question

The greatest number that will divide 242, 634 and 358, leaving the remainders 2, 4 and 8 respectively is:
O 10
35
O
70
O
45​

Answer 1

Answer:

Step-by-step explanation:

The greatest no. which divides 242,634 and 358 is the HCF of

242-2=240

634-4=630

358-8=350

The HCF of 240,630and 350is 10 as by applying Eulids division algorithm

Hence the greatest no. is 10.

Answer 2

Given:

The remainder left when the number divides 242, 634 and 358 = 2, 4 and 8

To find:

The greatest number that divides 242, 634, 358 leaving remainders 2, 4 and 8.

Solution:

We know that Dividend = Divisor* quotient + remainder

For the dividend to be completely divisible, the remainder must be subtracted from it :

242 - 2 = 240

634 - 4 = 630

358 - 8 = 350

The greatest number which divides 242,634 and 358 should be the HCF of  them.

240 = 2×2×2×2×3×5

630 = 2×3×3×5×7

350 = 2×5×5×7

HCF = 2×5 = 10

Therefore the required greatest number will be 10.