The greatest number that will divide 2930 and 3250 leaving remainder 7 and 11 respectively
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Hey!!!!
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Numbers we will use
=> 2930 - 7 = 2923
=> 3250 - 11 = 3239
Thus by Prime Factorisation Method
=> 2923 = 37 x 79
=> 3239 = 41 x 79
Thus HCF(2923,3239) = 79
Thus the greatest number that will divide 2930 and 3250 to leave 7 and 11 as remainder is 79.
_________
Hope this helps ✌️
__________
Numbers we will use
=> 2930 - 7 = 2923
=> 3250 - 11 = 3239
Thus by Prime Factorisation Method
=> 2923 = 37 x 79
=> 3239 = 41 x 79
Thus HCF(2923,3239) = 79
Thus the greatest number that will divide 2930 and 3250 to leave 7 and 11 as remainder is 79.
_________
Hope this helps ✌️
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