The greatest number that will divide 76, 112, 172 and 184 so as to leave remainder 40 in each case is 3K. Find the value of K.
Answers
Step-by-step explanation:
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Given:
The greatest number that will divide 76, 112, 172, and 184 to leave the remainder of 40 in each case is 3K
To Find:
The value of K.
Solution:
To find the number which will leave the remainder of 40 in each case
We will first subtract 40 from all the four numbers
76 - 40 = 36
112-40 = 72
172- 40 = 132
184- 40 = 144
Now, we will find the H.C.F (Highest Common Factor) of all the numbers
Let us factorize all the numbers
36 = 2×2×3×3
72= 2×2×2×3×3
132 = 2×2×3×11
144 = 2×2×2×2×3×3
In all the numbers 2×2×3 is common
So, H.C.F =2×2×3
=12
The greatest number that will divide 76, 112, 172, and 184 to leave the remainder of 40 in each case is 12
Now, it is given that the number is 3K
So,
So,
3K = 12
K = 4
Hence, the value of K = 4