Question

The greatest number which divides 2007 and 2627 leaving remainders 5 and 9 respectively is​

Answer 1

Answer:

The greatest number which divides 2007 and 2627 leaving remainders 5 and 9 respectively is 154

Step-by-step explanation:

2007 - 5 = 2002

2627 - 9 = 2618

HCF of 2002 and 2618 = 154

Answer 2

The greatest number which divides 2007 and 2627 leaving remainders 5 and 9 respectively is​ 154.

Given:

2007 and 2627

To find:

The greatest number which divides 2007 and 2627 leaving remainders 5 and 9 respectively is​

Solution:

We have to find the greatest number, so we have to find HCF of these numbers.

Now, some remainder is left, so we will subtract the remainder from number, so that number is divided completely.

2007 - 5 = 2002

2627-9 = 2618

So, our numbers are 2002 and 2618

2002 = 2*7*11*13

2618 = 2*7*11*17

Common factors are 2,7 and 11

HCF = 2*7*11 = 154.

Hence, 154 will divide these numbers.

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