Question

The greatest number which divides 963 and 615 leaving remainder as 4 in each case

Answer 1

Answer:

Real Numbers. Find the largest number which divides 615 and 963 leaving remainder 6 in each case. It is given that required number when divides 615 and 963, the remainder is 6 in each case. ⇒ 615 - 6 = 609 and 963 - 6 = 957 are completely divisible by the required number.

Answer 2

Answer:

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