The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:
A.123
B.127
C.235
D.305
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required number is = HCF of (1657-6) (2037-5)
= HCF of (1651)and (2032)
= 127
the greatest number is 127 and it's option B
= HCF of (1651)and (2032)
= 127
the greatest number is 127 and it's option B
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