The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:
A.123
B.127
C.235
D.305
Answers
Answered by
4
hello buddy here is your answer
Option B = 127
Required number = H.C.F. of (1657 - 6) and (2037 - 5)
H.C.F. of 1651 and 2032 = 127.
hope it helps
Option B = 127
Required number = H.C.F. of (1657 - 6) and (2037 - 5)
H.C.F. of 1651 and 2032 = 127.
hope it helps
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