Math, asked by sumiranpawan, 10 months ago

The greatest number which on dividing 1659 and 2036 leaves remainders 8 and 4?

Answers

Answered by suchindraraut17
123

Greatest number = 127

Step-by-step explanation:

Since,Remainders are 8 and 4

In the given question,

Greatest required number = H.C.F of (1659 - 8) and (2037 - 5)

                                           = H.C.F of 1651 and 2032

                                           = 127

Answered by lublana
93

The greatest number which on dividing 1659 and 2036 leaves remainder 8 and 4=127

Step-by-step explanation:

1659-8=1651

2036-4=2032

HCF of 1651 and 2032

Factors of 1651

1651=13\times 127

Factors of 2032

2032=2\times 2\times 2\times 2\times 127

Common factors of 1651 and 2032

127 and 1

Highest common factor of 1651 and 2032=127

HCF (1651,2032)=127

#Learns more:

https://brainly.in/question/14111162

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