The greatest number which on dividing 1659 and 2036 leaves remainders 8 and 4?
Answers
Answered by
123
Greatest number = 127
Step-by-step explanation:
Since,Remainders are 8 and 4
In the given question,
Greatest required number = H.C.F of (1659 - 8) and (2037 - 5)
= H.C.F of 1651 and 2032
= 127
Answered by
93
The greatest number which on dividing 1659 and 2036 leaves remainder 8 and 4=127
Step-by-step explanation:
1659-8=1651
2036-4=2032
HCF of 1651 and 2032
Factors of 1651
1651=
Factors of 2032
Common factors of 1651 and 2032
127 and 1
Highest common factor of 1651 and 2032=127
HCF (1651,2032)=127
#Learns more:
https://brainly.in/question/14111162
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